Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
Each number in C may only be used once in the combination.
Note:
- All numbers (including target) will be positive integers.
- Elements in a combination (a1, a2, … , ak) must be in non-descending order. (ie, a1 ≤ a2 ≤ … ≤ ak).
- The solution set must not contain duplicate combinations.
For example, given candidate set
A solution set is:
10,1,2,7,6,1,5 and target 8,A solution set is:
[1, 7][1, 2, 5][2, 6][1, 1, 6]
Java语言: CombinationSumII
01 public ArrayList<ArrayList<Integer>> combinationSum2(int[] num, int target) {
02 ArrayList<ArrayList<Integer>> results=new ArrayList<ArrayList<Integer>>();
03 if(num.length==0)
04 return results;
05 Arrays.sort(num);
06 ArrayList<Integer> temp=new ArrayList<Integer>();
07 doCombine(results, temp, num, target, 0);
08 return results;
09 }
10
11 public void doCombine(ArrayList<ArrayList<Integer>> results, ArrayList<Integer> temp, int [] num, int target, int start)
12 {
13 for(int i=start;i<num.length;i++)
14 {
15 if(target==num[i])
16 {
17 temp.add(num[i]);
18 ArrayList<Integer> out=new ArrayList<Integer>(temp);
19 if(!results.contains(out))
20 results.add(out);
21
22 }
23 else if(target>num[i])
24 {
25 temp.add(num[i]);
26 doCombine(results, temp, num, target-num[i], i+1);
27 }
28 else
29 {
30 return;
31 }
32
33 int size=temp.size();
34 if(size>0)
35 temp.remove(size-1);
36 }
37 }
02 ArrayList<ArrayList<Integer>> results=new ArrayList<ArrayList<Integer>>();
03 if(num.length==0)
04 return results;
05 Arrays.sort(num);
06 ArrayList<Integer> temp=new ArrayList<Integer>();
07 doCombine(results, temp, num, target, 0);
08 return results;
09 }
10
11 public void doCombine(ArrayList<ArrayList<Integer>> results, ArrayList<Integer> temp, int [] num, int target, int start)
12 {
13 for(int i=start;i<num.length;i++)
14 {
15 if(target==num[i])
16 {
17 temp.add(num[i]);
18 ArrayList<Integer> out=new ArrayList<Integer>(temp);
19 if(!results.contains(out))
20 results.add(out);
21
22 }
23 else if(target>num[i])
24 {
25 temp.add(num[i]);
26 doCombine(results, temp, num, target-num[i], i+1);
27 }
28 else
29 {
30 return;
31 }
32
33 int size=temp.size();
34 if(size>0)
35 temp.remove(size-1);
36 }
37 }
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